1 //===- InstCombineSimplifyDemanded.cpp ------------------------------------===//
2 //
3 // Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
4 // See https://llvm.org/LICENSE.txt for license information.
5 // SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
6 //
7 //===----------------------------------------------------------------------===//
8 //
9 // This file contains logic for simplifying instructions based on information
10 // about how they are used.
11 //
12 //===----------------------------------------------------------------------===//
13 
14 #include "InstCombineInternal.h"
15 #include "llvm/Analysis/ValueTracking.h"
16 #include "llvm/IR/GetElementPtrTypeIterator.h"
17 #include "llvm/IR/IntrinsicInst.h"
18 #include "llvm/IR/PatternMatch.h"
19 #include "llvm/Support/KnownBits.h"
20 #include "llvm/Transforms/InstCombine/InstCombiner.h"
21 
22 using namespace llvm;
23 using namespace llvm::PatternMatch;
24 
25 #define DEBUG_TYPE "instcombine"
26 
27 /// Check to see if the specified operand of the specified instruction is a
28 /// constant integer. If so, check to see if there are any bits set in the
29 /// constant that are not demanded. If so, shrink the constant and return true.
30 static bool ShrinkDemandedConstant(Instruction *I, unsigned OpNo,
31                                    const APInt &Demanded) {
32   assert(I && "No instruction?");
33   assert(OpNo < I->getNumOperands() && "Operand index too large");
34 
35   // The operand must be a constant integer or splat integer.
36   Value *Op = I->getOperand(OpNo);
37   const APInt *C;
38   if (!match(Op, m_APInt(C)))
39     return false;
40 
41   // If there are no bits set that aren't demanded, nothing to do.
42   if (C->isSubsetOf(Demanded))
43     return false;
44 
45   // This instruction is producing bits that are not demanded. Shrink the RHS.
46   I->setOperand(OpNo, ConstantInt::get(Op->getType(), *C & Demanded));
47 
48   return true;
49 }
50 
51 
52 
53 /// Inst is an integer instruction that SimplifyDemandedBits knows about. See if
54 /// the instruction has any properties that allow us to simplify its operands.
55 bool InstCombinerImpl::SimplifyDemandedInstructionBits(Instruction &Inst) {
56   unsigned BitWidth = Inst.getType()->getScalarSizeInBits();
57   KnownBits Known(BitWidth);
58   APInt DemandedMask(APInt::getAllOnes(BitWidth));
59 
60   Value *V = SimplifyDemandedUseBits(&Inst, DemandedMask, Known,
61                                      0, &Inst);
62   if (!V) return false;
63   if (V == &Inst) return true;
64   replaceInstUsesWith(Inst, V);
65   return true;
66 }
67 
68 /// This form of SimplifyDemandedBits simplifies the specified instruction
69 /// operand if possible, updating it in place. It returns true if it made any
70 /// change and false otherwise.
71 bool InstCombinerImpl::SimplifyDemandedBits(Instruction *I, unsigned OpNo,
72                                             const APInt &DemandedMask,
73                                             KnownBits &Known, unsigned Depth) {
74   Use &U = I->getOperandUse(OpNo);
75   Value *NewVal = SimplifyDemandedUseBits(U.get(), DemandedMask, Known,
76                                           Depth, I);
77   if (!NewVal) return false;
78   if (Instruction* OpInst = dyn_cast<Instruction>(U))
79     salvageDebugInfo(*OpInst);
80 
81   replaceUse(U, NewVal);
82   return true;
83 }
84 
85 /// This function attempts to replace V with a simpler value based on the
86 /// demanded bits. When this function is called, it is known that only the bits
87 /// set in DemandedMask of the result of V are ever used downstream.
88 /// Consequently, depending on the mask and V, it may be possible to replace V
89 /// with a constant or one of its operands. In such cases, this function does
90 /// the replacement and returns true. In all other cases, it returns false after
91 /// analyzing the expression and setting KnownOne and known to be one in the
92 /// expression. Known.Zero contains all the bits that are known to be zero in
93 /// the expression. These are provided to potentially allow the caller (which
94 /// might recursively be SimplifyDemandedBits itself) to simplify the
95 /// expression.
96 /// Known.One and Known.Zero always follow the invariant that:
97 ///   Known.One & Known.Zero == 0.
98 /// That is, a bit can't be both 1 and 0. Note that the bits in Known.One and
99 /// Known.Zero may only be accurate for those bits set in DemandedMask. Note
100 /// also that the bitwidth of V, DemandedMask, Known.Zero and Known.One must all
101 /// be the same.
102 ///
103 /// This returns null if it did not change anything and it permits no
104 /// simplification.  This returns V itself if it did some simplification of V's
105 /// operands based on the information about what bits are demanded. This returns
106 /// some other non-null value if it found out that V is equal to another value
107 /// in the context where the specified bits are demanded, but not for all users.
108 Value *InstCombinerImpl::SimplifyDemandedUseBits(Value *V, APInt DemandedMask,
109                                                  KnownBits &Known,
110                                                  unsigned Depth,
111                                                  Instruction *CxtI) {
112   assert(V != nullptr && "Null pointer of Value???");
113   assert(Depth <= MaxAnalysisRecursionDepth && "Limit Search Depth");
114   uint32_t BitWidth = DemandedMask.getBitWidth();
115   Type *VTy = V->getType();
116   assert(
117       (!VTy->isIntOrIntVectorTy() || VTy->getScalarSizeInBits() == BitWidth) &&
118       Known.getBitWidth() == BitWidth &&
119       "Value *V, DemandedMask and Known must have same BitWidth");
120 
121   if (isa<Constant>(V)) {
122     computeKnownBits(V, Known, Depth, CxtI);
123     return nullptr;
124   }
125 
126   Known.resetAll();
127   if (DemandedMask.isZero()) // Not demanding any bits from V.
128     return UndefValue::get(VTy);
129 
130   if (Depth == MaxAnalysisRecursionDepth)
131     return nullptr;
132 
133   if (isa<ScalableVectorType>(VTy))
134     return nullptr;
135 
136   Instruction *I = dyn_cast<Instruction>(V);
137   if (!I) {
138     computeKnownBits(V, Known, Depth, CxtI);
139     return nullptr;        // Only analyze instructions.
140   }
141 
142   // If there are multiple uses of this value and we aren't at the root, then
143   // we can't do any simplifications of the operands, because DemandedMask
144   // only reflects the bits demanded by *one* of the users.
145   if (Depth != 0 && !I->hasOneUse())
146     return SimplifyMultipleUseDemandedBits(I, DemandedMask, Known, Depth, CxtI);
147 
148   KnownBits LHSKnown(BitWidth), RHSKnown(BitWidth);
149 
150   // If this is the root being simplified, allow it to have multiple uses,
151   // just set the DemandedMask to all bits so that we can try to simplify the
152   // operands.  This allows visitTruncInst (for example) to simplify the
153   // operand of a trunc without duplicating all the logic below.
154   if (Depth == 0 && !V->hasOneUse())
155     DemandedMask.setAllBits();
156 
157   // If the high-bits of an ADD/SUB/MUL are not demanded, then we do not care
158   // about the high bits of the operands.
159   auto simplifyOperandsBasedOnUnusedHighBits = [&](APInt &DemandedFromOps) {
160     unsigned NLZ = DemandedMask.countLeadingZeros();
161     // Right fill the mask of bits for the operands to demand the most
162     // significant bit and all those below it.
163     DemandedFromOps = APInt::getLowBitsSet(BitWidth, BitWidth - NLZ);
164     if (ShrinkDemandedConstant(I, 0, DemandedFromOps) ||
165         SimplifyDemandedBits(I, 0, DemandedFromOps, LHSKnown, Depth + 1) ||
166         ShrinkDemandedConstant(I, 1, DemandedFromOps) ||
167         SimplifyDemandedBits(I, 1, DemandedFromOps, RHSKnown, Depth + 1)) {
168       if (NLZ > 0) {
169         // Disable the nsw and nuw flags here: We can no longer guarantee that
170         // we won't wrap after simplification. Removing the nsw/nuw flags is
171         // legal here because the top bit is not demanded.
172         I->setHasNoSignedWrap(false);
173         I->setHasNoUnsignedWrap(false);
174       }
175       return true;
176     }
177     return false;
178   };
179 
180   switch (I->getOpcode()) {
181   default:
182     computeKnownBits(I, Known, Depth, CxtI);
183     break;
184   case Instruction::And: {
185     // If either the LHS or the RHS are Zero, the result is zero.
186     if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnown, Depth + 1) ||
187         SimplifyDemandedBits(I, 0, DemandedMask & ~RHSKnown.Zero, LHSKnown,
188                              Depth + 1))
189       return I;
190     assert(!RHSKnown.hasConflict() && "Bits known to be one AND zero?");
191     assert(!LHSKnown.hasConflict() && "Bits known to be one AND zero?");
192 
193     Known = LHSKnown & RHSKnown;
194 
195     // If the client is only demanding bits that we know, return the known
196     // constant.
197     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
198       return Constant::getIntegerValue(VTy, Known.One);
199 
200     // If all of the demanded bits are known 1 on one side, return the other.
201     // These bits cannot contribute to the result of the 'and'.
202     if (DemandedMask.isSubsetOf(LHSKnown.Zero | RHSKnown.One))
203       return I->getOperand(0);
204     if (DemandedMask.isSubsetOf(RHSKnown.Zero | LHSKnown.One))
205       return I->getOperand(1);
206 
207     // If the RHS is a constant, see if we can simplify it.
208     if (ShrinkDemandedConstant(I, 1, DemandedMask & ~LHSKnown.Zero))
209       return I;
210 
211     break;
212   }
213   case Instruction::Or: {
214     // If either the LHS or the RHS are One, the result is One.
215     if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnown, Depth + 1) ||
216         SimplifyDemandedBits(I, 0, DemandedMask & ~RHSKnown.One, LHSKnown,
217                              Depth + 1))
218       return I;
219     assert(!RHSKnown.hasConflict() && "Bits known to be one AND zero?");
220     assert(!LHSKnown.hasConflict() && "Bits known to be one AND zero?");
221 
222     Known = LHSKnown | RHSKnown;
223 
224     // If the client is only demanding bits that we know, return the known
225     // constant.
226     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
227       return Constant::getIntegerValue(VTy, Known.One);
228 
229     // If all of the demanded bits are known zero on one side, return the other.
230     // These bits cannot contribute to the result of the 'or'.
231     if (DemandedMask.isSubsetOf(LHSKnown.One | RHSKnown.Zero))
232       return I->getOperand(0);
233     if (DemandedMask.isSubsetOf(RHSKnown.One | LHSKnown.Zero))
234       return I->getOperand(1);
235 
236     // If the RHS is a constant, see if we can simplify it.
237     if (ShrinkDemandedConstant(I, 1, DemandedMask))
238       return I;
239 
240     break;
241   }
242   case Instruction::Xor: {
243     if (SimplifyDemandedBits(I, 1, DemandedMask, RHSKnown, Depth + 1) ||
244         SimplifyDemandedBits(I, 0, DemandedMask, LHSKnown, Depth + 1))
245       return I;
246     Value *LHS, *RHS;
247     if (DemandedMask == 1 &&
248         match(I->getOperand(0), m_Intrinsic<Intrinsic::ctpop>(m_Value(LHS))) &&
249         match(I->getOperand(1), m_Intrinsic<Intrinsic::ctpop>(m_Value(RHS)))) {
250       // (ctpop(X) ^ ctpop(Y)) & 1 --> ctpop(X^Y) & 1
251       IRBuilderBase::InsertPointGuard Guard(Builder);
252       Builder.SetInsertPoint(I);
253       auto *Xor = Builder.CreateXor(LHS, RHS);
254       return Builder.CreateUnaryIntrinsic(Intrinsic::ctpop, Xor);
255     }
256 
257     assert(!RHSKnown.hasConflict() && "Bits known to be one AND zero?");
258     assert(!LHSKnown.hasConflict() && "Bits known to be one AND zero?");
259 
260     Known = LHSKnown ^ RHSKnown;
261 
262     // If the client is only demanding bits that we know, return the known
263     // constant.
264     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
265       return Constant::getIntegerValue(VTy, Known.One);
266 
267     // If all of the demanded bits are known zero on one side, return the other.
268     // These bits cannot contribute to the result of the 'xor'.
269     if (DemandedMask.isSubsetOf(RHSKnown.Zero))
270       return I->getOperand(0);
271     if (DemandedMask.isSubsetOf(LHSKnown.Zero))
272       return I->getOperand(1);
273 
274     // If all of the demanded bits are known to be zero on one side or the
275     // other, turn this into an *inclusive* or.
276     //    e.g. (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
277     if (DemandedMask.isSubsetOf(RHSKnown.Zero | LHSKnown.Zero)) {
278       Instruction *Or =
279         BinaryOperator::CreateOr(I->getOperand(0), I->getOperand(1),
280                                  I->getName());
281       return InsertNewInstWith(Or, *I);
282     }
283 
284     // If all of the demanded bits on one side are known, and all of the set
285     // bits on that side are also known to be set on the other side, turn this
286     // into an AND, as we know the bits will be cleared.
287     //    e.g. (X | C1) ^ C2 --> (X | C1) & ~C2 iff (C1&C2) == C2
288     if (DemandedMask.isSubsetOf(RHSKnown.Zero|RHSKnown.One) &&
289         RHSKnown.One.isSubsetOf(LHSKnown.One)) {
290       Constant *AndC = Constant::getIntegerValue(VTy,
291                                                  ~RHSKnown.One & DemandedMask);
292       Instruction *And = BinaryOperator::CreateAnd(I->getOperand(0), AndC);
293       return InsertNewInstWith(And, *I);
294     }
295 
296     // If the RHS is a constant, see if we can change it. Don't alter a -1
297     // constant because that's a canonical 'not' op, and that is better for
298     // combining, SCEV, and codegen.
299     const APInt *C;
300     if (match(I->getOperand(1), m_APInt(C)) && !C->isAllOnes()) {
301       if ((*C | ~DemandedMask).isAllOnes()) {
302         // Force bits to 1 to create a 'not' op.
303         I->setOperand(1, ConstantInt::getAllOnesValue(VTy));
304         return I;
305       }
306       // If we can't turn this into a 'not', try to shrink the constant.
307       if (ShrinkDemandedConstant(I, 1, DemandedMask))
308         return I;
309     }
310 
311     // If our LHS is an 'and' and if it has one use, and if any of the bits we
312     // are flipping are known to be set, then the xor is just resetting those
313     // bits to zero.  We can just knock out bits from the 'and' and the 'xor',
314     // simplifying both of them.
315     if (Instruction *LHSInst = dyn_cast<Instruction>(I->getOperand(0))) {
316       ConstantInt *AndRHS, *XorRHS;
317       if (LHSInst->getOpcode() == Instruction::And && LHSInst->hasOneUse() &&
318           match(I->getOperand(1), m_ConstantInt(XorRHS)) &&
319           match(LHSInst->getOperand(1), m_ConstantInt(AndRHS)) &&
320           (LHSKnown.One & RHSKnown.One & DemandedMask) != 0) {
321         APInt NewMask = ~(LHSKnown.One & RHSKnown.One & DemandedMask);
322 
323         Constant *AndC =
324             ConstantInt::get(I->getType(), NewMask & AndRHS->getValue());
325         Instruction *NewAnd = BinaryOperator::CreateAnd(I->getOperand(0), AndC);
326         InsertNewInstWith(NewAnd, *I);
327 
328         Constant *XorC =
329             ConstantInt::get(I->getType(), NewMask & XorRHS->getValue());
330         Instruction *NewXor = BinaryOperator::CreateXor(NewAnd, XorC);
331         return InsertNewInstWith(NewXor, *I);
332       }
333     }
334     break;
335   }
336   case Instruction::Select: {
337     if (SimplifyDemandedBits(I, 2, DemandedMask, RHSKnown, Depth + 1) ||
338         SimplifyDemandedBits(I, 1, DemandedMask, LHSKnown, Depth + 1))
339       return I;
340     assert(!RHSKnown.hasConflict() && "Bits known to be one AND zero?");
341     assert(!LHSKnown.hasConflict() && "Bits known to be one AND zero?");
342 
343     // If the operands are constants, see if we can simplify them.
344     // This is similar to ShrinkDemandedConstant, but for a select we want to
345     // try to keep the selected constants the same as icmp value constants, if
346     // we can. This helps not break apart (or helps put back together)
347     // canonical patterns like min and max.
348     auto CanonicalizeSelectConstant = [](Instruction *I, unsigned OpNo,
349                                          const APInt &DemandedMask) {
350       const APInt *SelC;
351       if (!match(I->getOperand(OpNo), m_APInt(SelC)))
352         return false;
353 
354       // Get the constant out of the ICmp, if there is one.
355       // Only try this when exactly 1 operand is a constant (if both operands
356       // are constant, the icmp should eventually simplify). Otherwise, we may
357       // invert the transform that reduces set bits and infinite-loop.
358       Value *X;
359       const APInt *CmpC;
360       ICmpInst::Predicate Pred;
361       if (!match(I->getOperand(0), m_ICmp(Pred, m_Value(X), m_APInt(CmpC))) ||
362           isa<Constant>(X) || CmpC->getBitWidth() != SelC->getBitWidth())
363         return ShrinkDemandedConstant(I, OpNo, DemandedMask);
364 
365       // If the constant is already the same as the ICmp, leave it as-is.
366       if (*CmpC == *SelC)
367         return false;
368       // If the constants are not already the same, but can be with the demand
369       // mask, use the constant value from the ICmp.
370       if ((*CmpC & DemandedMask) == (*SelC & DemandedMask)) {
371         I->setOperand(OpNo, ConstantInt::get(I->getType(), *CmpC));
372         return true;
373       }
374       return ShrinkDemandedConstant(I, OpNo, DemandedMask);
375     };
376     if (CanonicalizeSelectConstant(I, 1, DemandedMask) ||
377         CanonicalizeSelectConstant(I, 2, DemandedMask))
378       return I;
379 
380     // Only known if known in both the LHS and RHS.
381     Known = KnownBits::commonBits(LHSKnown, RHSKnown);
382     break;
383   }
384   case Instruction::Trunc: {
385     // If we do not demand the high bits of a right-shifted and truncated value,
386     // then we may be able to truncate it before the shift.
387     Value *X;
388     const APInt *C;
389     if (match(I->getOperand(0), m_OneUse(m_LShr(m_Value(X), m_APInt(C))))) {
390       // The shift amount must be valid (not poison) in the narrow type, and
391       // it must not be greater than the high bits demanded of the result.
392       if (C->ult(I->getType()->getScalarSizeInBits()) &&
393           C->ule(DemandedMask.countLeadingZeros())) {
394         // trunc (lshr X, C) --> lshr (trunc X), C
395         IRBuilderBase::InsertPointGuard Guard(Builder);
396         Builder.SetInsertPoint(I);
397         Value *Trunc = Builder.CreateTrunc(X, I->getType());
398         return Builder.CreateLShr(Trunc, C->getZExtValue());
399       }
400     }
401   }
402     LLVM_FALLTHROUGH;
403   case Instruction::ZExt: {
404     unsigned SrcBitWidth = I->getOperand(0)->getType()->getScalarSizeInBits();
405 
406     APInt InputDemandedMask = DemandedMask.zextOrTrunc(SrcBitWidth);
407     KnownBits InputKnown(SrcBitWidth);
408     if (SimplifyDemandedBits(I, 0, InputDemandedMask, InputKnown, Depth + 1))
409       return I;
410     assert(InputKnown.getBitWidth() == SrcBitWidth && "Src width changed?");
411     Known = InputKnown.zextOrTrunc(BitWidth);
412     assert(!Known.hasConflict() && "Bits known to be one AND zero?");
413     break;
414   }
415   case Instruction::BitCast:
416     if (!I->getOperand(0)->getType()->isIntOrIntVectorTy())
417       return nullptr;  // vector->int or fp->int?
418 
419     if (VectorType *DstVTy = dyn_cast<VectorType>(I->getType())) {
420       if (VectorType *SrcVTy =
421             dyn_cast<VectorType>(I->getOperand(0)->getType())) {
422         if (cast<FixedVectorType>(DstVTy)->getNumElements() !=
423             cast<FixedVectorType>(SrcVTy)->getNumElements())
424           // Don't touch a bitcast between vectors of different element counts.
425           return nullptr;
426       } else
427         // Don't touch a scalar-to-vector bitcast.
428         return nullptr;
429     } else if (I->getOperand(0)->getType()->isVectorTy())
430       // Don't touch a vector-to-scalar bitcast.
431       return nullptr;
432 
433     if (SimplifyDemandedBits(I, 0, DemandedMask, Known, Depth + 1))
434       return I;
435     assert(!Known.hasConflict() && "Bits known to be one AND zero?");
436     break;
437   case Instruction::SExt: {
438     // Compute the bits in the result that are not present in the input.
439     unsigned SrcBitWidth = I->getOperand(0)->getType()->getScalarSizeInBits();
440 
441     APInt InputDemandedBits = DemandedMask.trunc(SrcBitWidth);
442 
443     // If any of the sign extended bits are demanded, we know that the sign
444     // bit is demanded.
445     if (DemandedMask.getActiveBits() > SrcBitWidth)
446       InputDemandedBits.setBit(SrcBitWidth-1);
447 
448     KnownBits InputKnown(SrcBitWidth);
449     if (SimplifyDemandedBits(I, 0, InputDemandedBits, InputKnown, Depth + 1))
450       return I;
451 
452     // If the input sign bit is known zero, or if the NewBits are not demanded
453     // convert this into a zero extension.
454     if (InputKnown.isNonNegative() ||
455         DemandedMask.getActiveBits() <= SrcBitWidth) {
456       // Convert to ZExt cast.
457       CastInst *NewCast = new ZExtInst(I->getOperand(0), VTy, I->getName());
458       return InsertNewInstWith(NewCast, *I);
459      }
460 
461     // If the sign bit of the input is known set or clear, then we know the
462     // top bits of the result.
463     Known = InputKnown.sext(BitWidth);
464     assert(!Known.hasConflict() && "Bits known to be one AND zero?");
465     break;
466   }
467   case Instruction::Add:
468     if ((DemandedMask & 1) == 0) {
469       // If we do not need the low bit, try to convert bool math to logic:
470       // add iN (zext i1 X), (sext i1 Y) --> sext (~X & Y) to iN
471       Value *X, *Y;
472       if (match(I, m_c_Add(m_OneUse(m_ZExt(m_Value(X))),
473                            m_OneUse(m_SExt(m_Value(Y))))) &&
474           X->getType()->isIntOrIntVectorTy(1) && X->getType() == Y->getType()) {
475         // Truth table for inputs and output signbits:
476         //       X:0 | X:1
477         //      ----------
478         // Y:0  |  0 | 0 |
479         // Y:1  | -1 | 0 |
480         //      ----------
481         IRBuilderBase::InsertPointGuard Guard(Builder);
482         Builder.SetInsertPoint(I);
483         Value *AndNot = Builder.CreateAnd(Builder.CreateNot(X), Y);
484         return Builder.CreateSExt(AndNot, VTy);
485       }
486 
487       // add iN (sext i1 X), (sext i1 Y) --> sext (X | Y) to iN
488       // TODO: Relax the one-use checks because we are removing an instruction?
489       if (match(I, m_Add(m_OneUse(m_SExt(m_Value(X))),
490                          m_OneUse(m_SExt(m_Value(Y))))) &&
491           X->getType()->isIntOrIntVectorTy(1) && X->getType() == Y->getType()) {
492         // Truth table for inputs and output signbits:
493         //       X:0 | X:1
494         //      -----------
495         // Y:0  | -1 | -1 |
496         // Y:1  | -1 |  0 |
497         //      -----------
498         IRBuilderBase::InsertPointGuard Guard(Builder);
499         Builder.SetInsertPoint(I);
500         Value *Or = Builder.CreateOr(X, Y);
501         return Builder.CreateSExt(Or, VTy);
502       }
503     }
504     LLVM_FALLTHROUGH;
505   case Instruction::Sub: {
506     APInt DemandedFromOps;
507     if (simplifyOperandsBasedOnUnusedHighBits(DemandedFromOps))
508       return I;
509 
510     // If we are known to be adding/subtracting zeros to every bit below
511     // the highest demanded bit, we just return the other side.
512     if (DemandedFromOps.isSubsetOf(RHSKnown.Zero))
513       return I->getOperand(0);
514     // We can't do this with the LHS for subtraction, unless we are only
515     // demanding the LSB.
516     if ((I->getOpcode() == Instruction::Add || DemandedFromOps.isOne()) &&
517         DemandedFromOps.isSubsetOf(LHSKnown.Zero))
518       return I->getOperand(1);
519 
520     // Otherwise just compute the known bits of the result.
521     bool NSW = cast<OverflowingBinaryOperator>(I)->hasNoSignedWrap();
522     Known = KnownBits::computeForAddSub(I->getOpcode() == Instruction::Add,
523                                         NSW, LHSKnown, RHSKnown);
524     break;
525   }
526   case Instruction::Mul: {
527     APInt DemandedFromOps;
528     if (simplifyOperandsBasedOnUnusedHighBits(DemandedFromOps))
529       return I;
530 
531     if (DemandedMask.isPowerOf2()) {
532       // The LSB of X*Y is set only if (X & 1) == 1 and (Y & 1) == 1.
533       // If we demand exactly one bit N and we have "X * (C' << N)" where C' is
534       // odd (has LSB set), then the left-shifted low bit of X is the answer.
535       unsigned CTZ = DemandedMask.countTrailingZeros();
536       const APInt *C;
537       if (match(I->getOperand(1), m_APInt(C)) &&
538           C->countTrailingZeros() == CTZ) {
539         Constant *ShiftC = ConstantInt::get(I->getType(), CTZ);
540         Instruction *Shl = BinaryOperator::CreateShl(I->getOperand(0), ShiftC);
541         return InsertNewInstWith(Shl, *I);
542       }
543     }
544     // For a squared value "X * X", the bottom 2 bits are 0 and X[0] because:
545     // X * X is odd iff X is odd.
546     // 'Quadratic Reciprocity': X * X -> 0 for bit[1]
547     if (I->getOperand(0) == I->getOperand(1) && DemandedMask.ult(4)) {
548       Constant *One = ConstantInt::get(VTy, 1);
549       Instruction *And1 = BinaryOperator::CreateAnd(I->getOperand(0), One);
550       return InsertNewInstWith(And1, *I);
551     }
552 
553     computeKnownBits(I, Known, Depth, CxtI);
554     break;
555   }
556   case Instruction::Shl: {
557     const APInt *SA;
558     if (match(I->getOperand(1), m_APInt(SA))) {
559       const APInt *ShrAmt;
560       if (match(I->getOperand(0), m_Shr(m_Value(), m_APInt(ShrAmt))))
561         if (Instruction *Shr = dyn_cast<Instruction>(I->getOperand(0)))
562           if (Value *R = simplifyShrShlDemandedBits(Shr, *ShrAmt, I, *SA,
563                                                     DemandedMask, Known))
564             return R;
565 
566       // TODO: If we only want bits that already match the signbit then we don't
567       // need to shift.
568 
569       uint64_t ShiftAmt = SA->getLimitedValue(BitWidth-1);
570       APInt DemandedMaskIn(DemandedMask.lshr(ShiftAmt));
571 
572       // If the shift is NUW/NSW, then it does demand the high bits.
573       ShlOperator *IOp = cast<ShlOperator>(I);
574       if (IOp->hasNoSignedWrap())
575         DemandedMaskIn.setHighBits(ShiftAmt+1);
576       else if (IOp->hasNoUnsignedWrap())
577         DemandedMaskIn.setHighBits(ShiftAmt);
578 
579       if (SimplifyDemandedBits(I, 0, DemandedMaskIn, Known, Depth + 1))
580         return I;
581       assert(!Known.hasConflict() && "Bits known to be one AND zero?");
582 
583       bool SignBitZero = Known.Zero.isSignBitSet();
584       bool SignBitOne = Known.One.isSignBitSet();
585       Known.Zero <<= ShiftAmt;
586       Known.One  <<= ShiftAmt;
587       // low bits known zero.
588       if (ShiftAmt)
589         Known.Zero.setLowBits(ShiftAmt);
590 
591       // If this shift has "nsw" keyword, then the result is either a poison
592       // value or has the same sign bit as the first operand.
593       if (IOp->hasNoSignedWrap()) {
594         if (SignBitZero)
595           Known.Zero.setSignBit();
596         else if (SignBitOne)
597           Known.One.setSignBit();
598         if (Known.hasConflict())
599           return UndefValue::get(I->getType());
600       }
601     } else {
602       // This is a variable shift, so we can't shift the demand mask by a known
603       // amount. But if we are not demanding high bits, then we are not
604       // demanding those bits from the pre-shifted operand either.
605       if (unsigned CTLZ = DemandedMask.countLeadingZeros()) {
606         APInt DemandedFromOp(APInt::getLowBitsSet(BitWidth, BitWidth - CTLZ));
607         if (SimplifyDemandedBits(I, 0, DemandedFromOp, Known, Depth + 1)) {
608           // We can't guarantee that nsw/nuw hold after simplifying the operand.
609           I->dropPoisonGeneratingFlags();
610           return I;
611         }
612       }
613       computeKnownBits(I, Known, Depth, CxtI);
614     }
615     break;
616   }
617   case Instruction::LShr: {
618     const APInt *SA;
619     if (match(I->getOperand(1), m_APInt(SA))) {
620       uint64_t ShiftAmt = SA->getLimitedValue(BitWidth-1);
621 
622       // If we are just demanding the shifted sign bit and below, then this can
623       // be treated as an ASHR in disguise.
624       if (DemandedMask.countLeadingZeros() >= ShiftAmt) {
625         // If we only want bits that already match the signbit then we don't
626         // need to shift.
627         unsigned NumHiDemandedBits =
628             BitWidth - DemandedMask.countTrailingZeros();
629         unsigned SignBits =
630             ComputeNumSignBits(I->getOperand(0), Depth + 1, CxtI);
631         if (SignBits >= NumHiDemandedBits)
632           return I->getOperand(0);
633       }
634 
635       // Unsigned shift right.
636       APInt DemandedMaskIn(DemandedMask.shl(ShiftAmt));
637 
638       // If the shift is exact, then it does demand the low bits (and knows that
639       // they are zero).
640       if (cast<LShrOperator>(I)->isExact())
641         DemandedMaskIn.setLowBits(ShiftAmt);
642 
643       if (SimplifyDemandedBits(I, 0, DemandedMaskIn, Known, Depth + 1))
644         return I;
645       assert(!Known.hasConflict() && "Bits known to be one AND zero?");
646       Known.Zero.lshrInPlace(ShiftAmt);
647       Known.One.lshrInPlace(ShiftAmt);
648       if (ShiftAmt)
649         Known.Zero.setHighBits(ShiftAmt);  // high bits known zero.
650     } else {
651       computeKnownBits(I, Known, Depth, CxtI);
652     }
653     break;
654   }
655   case Instruction::AShr: {
656     unsigned SignBits = ComputeNumSignBits(I->getOperand(0), Depth + 1, CxtI);
657 
658     // If we only want bits that already match the signbit then we don't need
659     // to shift.
660     unsigned NumHiDemandedBits = BitWidth - DemandedMask.countTrailingZeros();
661     if (SignBits >= NumHiDemandedBits)
662       return I->getOperand(0);
663 
664     // If this is an arithmetic shift right and only the low-bit is set, we can
665     // always convert this into a logical shr, even if the shift amount is
666     // variable.  The low bit of the shift cannot be an input sign bit unless
667     // the shift amount is >= the size of the datatype, which is undefined.
668     if (DemandedMask.isOne()) {
669       // Perform the logical shift right.
670       Instruction *NewVal = BinaryOperator::CreateLShr(
671                         I->getOperand(0), I->getOperand(1), I->getName());
672       return InsertNewInstWith(NewVal, *I);
673     }
674 
675     const APInt *SA;
676     if (match(I->getOperand(1), m_APInt(SA))) {
677       uint32_t ShiftAmt = SA->getLimitedValue(BitWidth-1);
678 
679       // Signed shift right.
680       APInt DemandedMaskIn(DemandedMask.shl(ShiftAmt));
681       // If any of the high bits are demanded, we should set the sign bit as
682       // demanded.
683       if (DemandedMask.countLeadingZeros() <= ShiftAmt)
684         DemandedMaskIn.setSignBit();
685 
686       // If the shift is exact, then it does demand the low bits (and knows that
687       // they are zero).
688       if (cast<AShrOperator>(I)->isExact())
689         DemandedMaskIn.setLowBits(ShiftAmt);
690 
691       if (SimplifyDemandedBits(I, 0, DemandedMaskIn, Known, Depth + 1))
692         return I;
693 
694       assert(!Known.hasConflict() && "Bits known to be one AND zero?");
695       // Compute the new bits that are at the top now plus sign bits.
696       APInt HighBits(APInt::getHighBitsSet(
697           BitWidth, std::min(SignBits + ShiftAmt - 1, BitWidth)));
698       Known.Zero.lshrInPlace(ShiftAmt);
699       Known.One.lshrInPlace(ShiftAmt);
700 
701       // If the input sign bit is known to be zero, or if none of the top bits
702       // are demanded, turn this into an unsigned shift right.
703       assert(BitWidth > ShiftAmt && "Shift amount not saturated?");
704       if (Known.Zero[BitWidth-ShiftAmt-1] ||
705           !DemandedMask.intersects(HighBits)) {
706         BinaryOperator *LShr = BinaryOperator::CreateLShr(I->getOperand(0),
707                                                           I->getOperand(1));
708         LShr->setIsExact(cast<BinaryOperator>(I)->isExact());
709         return InsertNewInstWith(LShr, *I);
710       } else if (Known.One[BitWidth-ShiftAmt-1]) { // New bits are known one.
711         Known.One |= HighBits;
712       }
713     } else {
714       computeKnownBits(I, Known, Depth, CxtI);
715     }
716     break;
717   }
718   case Instruction::UDiv: {
719     // UDiv doesn't demand low bits that are zero in the divisor.
720     const APInt *SA;
721     if (match(I->getOperand(1), m_APInt(SA))) {
722       // If the shift is exact, then it does demand the low bits.
723       if (cast<UDivOperator>(I)->isExact())
724         break;
725 
726       // FIXME: Take the demanded mask of the result into account.
727       unsigned RHSTrailingZeros = SA->countTrailingZeros();
728       APInt DemandedMaskIn =
729           APInt::getHighBitsSet(BitWidth, BitWidth - RHSTrailingZeros);
730       if (SimplifyDemandedBits(I, 0, DemandedMaskIn, LHSKnown, Depth + 1))
731         return I;
732 
733       // Propagate zero bits from the input.
734       Known.Zero.setHighBits(std::min(
735           BitWidth, LHSKnown.Zero.countLeadingOnes() + RHSTrailingZeros));
736     } else {
737       computeKnownBits(I, Known, Depth, CxtI);
738     }
739     break;
740   }
741   case Instruction::SRem: {
742     const APInt *Rem;
743     if (match(I->getOperand(1), m_APInt(Rem))) {
744       // X % -1 demands all the bits because we don't want to introduce
745       // INT_MIN % -1 (== undef) by accident.
746       if (Rem->isAllOnes())
747         break;
748       APInt RA = Rem->abs();
749       if (RA.isPowerOf2()) {
750         if (DemandedMask.ult(RA))    // srem won't affect demanded bits
751           return I->getOperand(0);
752 
753         APInt LowBits = RA - 1;
754         APInt Mask2 = LowBits | APInt::getSignMask(BitWidth);
755         if (SimplifyDemandedBits(I, 0, Mask2, LHSKnown, Depth + 1))
756           return I;
757 
758         // The low bits of LHS are unchanged by the srem.
759         Known.Zero = LHSKnown.Zero & LowBits;
760         Known.One = LHSKnown.One & LowBits;
761 
762         // If LHS is non-negative or has all low bits zero, then the upper bits
763         // are all zero.
764         if (LHSKnown.isNonNegative() || LowBits.isSubsetOf(LHSKnown.Zero))
765           Known.Zero |= ~LowBits;
766 
767         // If LHS is negative and not all low bits are zero, then the upper bits
768         // are all one.
769         if (LHSKnown.isNegative() && LowBits.intersects(LHSKnown.One))
770           Known.One |= ~LowBits;
771 
772         assert(!Known.hasConflict() && "Bits known to be one AND zero?");
773         break;
774       }
775     }
776 
777     // The sign bit is the LHS's sign bit, except when the result of the
778     // remainder is zero.
779     if (DemandedMask.isSignBitSet()) {
780       computeKnownBits(I->getOperand(0), LHSKnown, Depth + 1, CxtI);
781       // If it's known zero, our sign bit is also zero.
782       if (LHSKnown.isNonNegative())
783         Known.makeNonNegative();
784     }
785     break;
786   }
787   case Instruction::URem: {
788     KnownBits Known2(BitWidth);
789     APInt AllOnes = APInt::getAllOnes(BitWidth);
790     if (SimplifyDemandedBits(I, 0, AllOnes, Known2, Depth + 1) ||
791         SimplifyDemandedBits(I, 1, AllOnes, Known2, Depth + 1))
792       return I;
793 
794     unsigned Leaders = Known2.countMinLeadingZeros();
795     Known.Zero = APInt::getHighBitsSet(BitWidth, Leaders) & DemandedMask;
796     break;
797   }
798   case Instruction::Call: {
799     bool KnownBitsComputed = false;
800     if (IntrinsicInst *II = dyn_cast<IntrinsicInst>(I)) {
801       switch (II->getIntrinsicID()) {
802       case Intrinsic::abs: {
803         if (DemandedMask == 1)
804           return II->getArgOperand(0);
805         break;
806       }
807       case Intrinsic::ctpop: {
808         // Checking if the number of clear bits is odd (parity)? If the type has
809         // an even number of bits, that's the same as checking if the number of
810         // set bits is odd, so we can eliminate the 'not' op.
811         Value *X;
812         if (DemandedMask == 1 && VTy->getScalarSizeInBits() % 2 == 0 &&
813             match(II->getArgOperand(0), m_Not(m_Value(X)))) {
814           Function *Ctpop = Intrinsic::getDeclaration(
815               II->getModule(), Intrinsic::ctpop, II->getType());
816           return InsertNewInstWith(CallInst::Create(Ctpop, {X}), *I);
817         }
818         break;
819       }
820       case Intrinsic::bswap: {
821         // If the only bits demanded come from one byte of the bswap result,
822         // just shift the input byte into position to eliminate the bswap.
823         unsigned NLZ = DemandedMask.countLeadingZeros();
824         unsigned NTZ = DemandedMask.countTrailingZeros();
825 
826         // Round NTZ down to the next byte.  If we have 11 trailing zeros, then
827         // we need all the bits down to bit 8.  Likewise, round NLZ.  If we
828         // have 14 leading zeros, round to 8.
829         NLZ = alignDown(NLZ, 8);
830         NTZ = alignDown(NTZ, 8);
831         // If we need exactly one byte, we can do this transformation.
832         if (BitWidth - NLZ - NTZ == 8) {
833           // Replace this with either a left or right shift to get the byte into
834           // the right place.
835           Instruction *NewVal;
836           if (NLZ > NTZ)
837             NewVal = BinaryOperator::CreateLShr(
838                 II->getArgOperand(0),
839                 ConstantInt::get(I->getType(), NLZ - NTZ));
840           else
841             NewVal = BinaryOperator::CreateShl(
842                 II->getArgOperand(0),
843                 ConstantInt::get(I->getType(), NTZ - NLZ));
844           NewVal->takeName(I);
845           return InsertNewInstWith(NewVal, *I);
846         }
847         break;
848       }
849       case Intrinsic::fshr:
850       case Intrinsic::fshl: {
851         const APInt *SA;
852         if (!match(I->getOperand(2), m_APInt(SA)))
853           break;
854 
855         // Normalize to funnel shift left. APInt shifts of BitWidth are well-
856         // defined, so no need to special-case zero shifts here.
857         uint64_t ShiftAmt = SA->urem(BitWidth);
858         if (II->getIntrinsicID() == Intrinsic::fshr)
859           ShiftAmt = BitWidth - ShiftAmt;
860 
861         APInt DemandedMaskLHS(DemandedMask.lshr(ShiftAmt));
862         APInt DemandedMaskRHS(DemandedMask.shl(BitWidth - ShiftAmt));
863         if (SimplifyDemandedBits(I, 0, DemandedMaskLHS, LHSKnown, Depth + 1) ||
864             SimplifyDemandedBits(I, 1, DemandedMaskRHS, RHSKnown, Depth + 1))
865           return I;
866 
867         Known.Zero = LHSKnown.Zero.shl(ShiftAmt) |
868                      RHSKnown.Zero.lshr(BitWidth - ShiftAmt);
869         Known.One = LHSKnown.One.shl(ShiftAmt) |
870                     RHSKnown.One.lshr(BitWidth - ShiftAmt);
871         KnownBitsComputed = true;
872         break;
873       }
874       case Intrinsic::umax: {
875         // UMax(A, C) == A if ...
876         // The lowest non-zero bit of DemandMask is higher than the highest
877         // non-zero bit of C.
878         const APInt *C;
879         unsigned CTZ = DemandedMask.countTrailingZeros();
880         if (match(II->getArgOperand(1), m_APInt(C)) &&
881             CTZ >= C->getActiveBits())
882           return II->getArgOperand(0);
883         break;
884       }
885       case Intrinsic::umin: {
886         // UMin(A, C) == A if ...
887         // The lowest non-zero bit of DemandMask is higher than the highest
888         // non-one bit of C.
889         // This comes from using DeMorgans on the above umax example.
890         const APInt *C;
891         unsigned CTZ = DemandedMask.countTrailingZeros();
892         if (match(II->getArgOperand(1), m_APInt(C)) &&
893             CTZ >= C->getBitWidth() - C->countLeadingOnes())
894           return II->getArgOperand(0);
895         break;
896       }
897       default: {
898         // Handle target specific intrinsics
899         Optional<Value *> V = targetSimplifyDemandedUseBitsIntrinsic(
900             *II, DemandedMask, Known, KnownBitsComputed);
901         if (V.hasValue())
902           return V.getValue();
903         break;
904       }
905       }
906     }
907 
908     if (!KnownBitsComputed)
909       computeKnownBits(V, Known, Depth, CxtI);
910     break;
911   }
912   }
913 
914   // If the client is only demanding bits that we know, return the known
915   // constant.
916   if (DemandedMask.isSubsetOf(Known.Zero|Known.One))
917     return Constant::getIntegerValue(VTy, Known.One);
918   return nullptr;
919 }
920 
921 /// Helper routine of SimplifyDemandedUseBits. It computes Known
922 /// bits. It also tries to handle simplifications that can be done based on
923 /// DemandedMask, but without modifying the Instruction.
924 Value *InstCombinerImpl::SimplifyMultipleUseDemandedBits(
925     Instruction *I, const APInt &DemandedMask, KnownBits &Known, unsigned Depth,
926     Instruction *CxtI) {
927   unsigned BitWidth = DemandedMask.getBitWidth();
928   Type *ITy = I->getType();
929 
930   KnownBits LHSKnown(BitWidth);
931   KnownBits RHSKnown(BitWidth);
932 
933   // Despite the fact that we can't simplify this instruction in all User's
934   // context, we can at least compute the known bits, and we can
935   // do simplifications that apply to *just* the one user if we know that
936   // this instruction has a simpler value in that context.
937   switch (I->getOpcode()) {
938   case Instruction::And: {
939     // If either the LHS or the RHS are Zero, the result is zero.
940     computeKnownBits(I->getOperand(1), RHSKnown, Depth + 1, CxtI);
941     computeKnownBits(I->getOperand(0), LHSKnown, Depth + 1,
942                      CxtI);
943 
944     Known = LHSKnown & RHSKnown;
945 
946     // If the client is only demanding bits that we know, return the known
947     // constant.
948     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
949       return Constant::getIntegerValue(ITy, Known.One);
950 
951     // If all of the demanded bits are known 1 on one side, return the other.
952     // These bits cannot contribute to the result of the 'and' in this
953     // context.
954     if (DemandedMask.isSubsetOf(LHSKnown.Zero | RHSKnown.One))
955       return I->getOperand(0);
956     if (DemandedMask.isSubsetOf(RHSKnown.Zero | LHSKnown.One))
957       return I->getOperand(1);
958 
959     break;
960   }
961   case Instruction::Or: {
962     // We can simplify (X|Y) -> X or Y in the user's context if we know that
963     // only bits from X or Y are demanded.
964 
965     // If either the LHS or the RHS are One, the result is One.
966     computeKnownBits(I->getOperand(1), RHSKnown, Depth + 1, CxtI);
967     computeKnownBits(I->getOperand(0), LHSKnown, Depth + 1,
968                      CxtI);
969 
970     Known = LHSKnown | RHSKnown;
971 
972     // If the client is only demanding bits that we know, return the known
973     // constant.
974     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
975       return Constant::getIntegerValue(ITy, Known.One);
976 
977     // If all of the demanded bits are known zero on one side, return the
978     // other.  These bits cannot contribute to the result of the 'or' in this
979     // context.
980     if (DemandedMask.isSubsetOf(LHSKnown.One | RHSKnown.Zero))
981       return I->getOperand(0);
982     if (DemandedMask.isSubsetOf(RHSKnown.One | LHSKnown.Zero))
983       return I->getOperand(1);
984 
985     break;
986   }
987   case Instruction::Xor: {
988     // We can simplify (X^Y) -> X or Y in the user's context if we know that
989     // only bits from X or Y are demanded.
990 
991     computeKnownBits(I->getOperand(1), RHSKnown, Depth + 1, CxtI);
992     computeKnownBits(I->getOperand(0), LHSKnown, Depth + 1,
993                      CxtI);
994 
995     Known = LHSKnown ^ RHSKnown;
996 
997     // If the client is only demanding bits that we know, return the known
998     // constant.
999     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
1000       return Constant::getIntegerValue(ITy, Known.One);
1001 
1002     // If all of the demanded bits are known zero on one side, return the
1003     // other.
1004     if (DemandedMask.isSubsetOf(RHSKnown.Zero))
1005       return I->getOperand(0);
1006     if (DemandedMask.isSubsetOf(LHSKnown.Zero))
1007       return I->getOperand(1);
1008 
1009     break;
1010   }
1011   case Instruction::AShr: {
1012     // Compute the Known bits to simplify things downstream.
1013     computeKnownBits(I, Known, Depth, CxtI);
1014 
1015     // If this user is only demanding bits that we know, return the known
1016     // constant.
1017     if (DemandedMask.isSubsetOf(Known.Zero | Known.One))
1018       return Constant::getIntegerValue(ITy, Known.One);
1019 
1020     // If the right shift operand 0 is a result of a left shift by the same
1021     // amount, this is probably a zero/sign extension, which may be unnecessary,
1022     // if we do not demand any of the new sign bits. So, return the original
1023     // operand instead.
1024     const APInt *ShiftRC;
1025     const APInt *ShiftLC;
1026     Value *X;
1027     unsigned BitWidth = DemandedMask.getBitWidth();
1028     if (match(I,
1029               m_AShr(m_Shl(m_Value(X), m_APInt(ShiftLC)), m_APInt(ShiftRC))) &&
1030         ShiftLC == ShiftRC && ShiftLC->ult(BitWidth) &&
1031         DemandedMask.isSubsetOf(APInt::getLowBitsSet(
1032             BitWidth, BitWidth - ShiftRC->getZExtValue()))) {
1033       return X;
1034     }
1035 
1036     break;
1037   }
1038   default:
1039     // Compute the Known bits to simplify things downstream.
1040     computeKnownBits(I, Known, Depth, CxtI);
1041 
1042     // If this user is only demanding bits that we know, return the known
1043     // constant.
1044     if (DemandedMask.isSubsetOf(Known.Zero|Known.One))
1045       return Constant::getIntegerValue(ITy, Known.One);
1046 
1047     break;
1048   }
1049 
1050   return nullptr;
1051 }
1052 
1053 /// Helper routine of SimplifyDemandedUseBits. It tries to simplify
1054 /// "E1 = (X lsr C1) << C2", where the C1 and C2 are constant, into
1055 /// "E2 = X << (C2 - C1)" or "E2 = X >> (C1 - C2)", depending on the sign
1056 /// of "C2-C1".
1057 ///
1058 /// Suppose E1 and E2 are generally different in bits S={bm, bm+1,
1059 /// ..., bn}, without considering the specific value X is holding.
1060 /// This transformation is legal iff one of following conditions is hold:
1061 ///  1) All the bit in S are 0, in this case E1 == E2.
1062 ///  2) We don't care those bits in S, per the input DemandedMask.
1063 ///  3) Combination of 1) and 2). Some bits in S are 0, and we don't care the
1064 ///     rest bits.
1065 ///
1066 /// Currently we only test condition 2).
1067 ///
1068 /// As with SimplifyDemandedUseBits, it returns NULL if the simplification was
1069 /// not successful.
1070 Value *InstCombinerImpl::simplifyShrShlDemandedBits(
1071     Instruction *Shr, const APInt &ShrOp1, Instruction *Shl,
1072     const APInt &ShlOp1, const APInt &DemandedMask, KnownBits &Known) {
1073   if (!ShlOp1 || !ShrOp1)
1074     return nullptr; // No-op.
1075 
1076   Value *VarX = Shr->getOperand(0);
1077   Type *Ty = VarX->getType();
1078   unsigned BitWidth = Ty->getScalarSizeInBits();
1079   if (ShlOp1.uge(BitWidth) || ShrOp1.uge(BitWidth))
1080     return nullptr; // Undef.
1081 
1082   unsigned ShlAmt = ShlOp1.getZExtValue();
1083   unsigned ShrAmt = ShrOp1.getZExtValue();
1084 
1085   Known.One.clearAllBits();
1086   Known.Zero.setLowBits(ShlAmt - 1);
1087   Known.Zero &= DemandedMask;
1088 
1089   APInt BitMask1(APInt::getAllOnes(BitWidth));
1090   APInt BitMask2(APInt::getAllOnes(BitWidth));
1091 
1092   bool isLshr = (Shr->getOpcode() == Instruction::LShr);
1093   BitMask1 = isLshr ? (BitMask1.lshr(ShrAmt) << ShlAmt) :
1094                       (BitMask1.ashr(ShrAmt) << ShlAmt);
1095 
1096   if (ShrAmt <= ShlAmt) {
1097     BitMask2 <<= (ShlAmt - ShrAmt);
1098   } else {
1099     BitMask2 = isLshr ? BitMask2.lshr(ShrAmt - ShlAmt):
1100                         BitMask2.ashr(ShrAmt - ShlAmt);
1101   }
1102 
1103   // Check if condition-2 (see the comment to this function) is satified.
1104   if ((BitMask1 & DemandedMask) == (BitMask2 & DemandedMask)) {
1105     if (ShrAmt == ShlAmt)
1106       return VarX;
1107 
1108     if (!Shr->hasOneUse())
1109       return nullptr;
1110 
1111     BinaryOperator *New;
1112     if (ShrAmt < ShlAmt) {
1113       Constant *Amt = ConstantInt::get(VarX->getType(), ShlAmt - ShrAmt);
1114       New = BinaryOperator::CreateShl(VarX, Amt);
1115       BinaryOperator *Orig = cast<BinaryOperator>(Shl);
1116       New->setHasNoSignedWrap(Orig->hasNoSignedWrap());
1117       New->setHasNoUnsignedWrap(Orig->hasNoUnsignedWrap());
1118     } else {
1119       Constant *Amt = ConstantInt::get(VarX->getType(), ShrAmt - ShlAmt);
1120       New = isLshr ? BinaryOperator::CreateLShr(VarX, Amt) :
1121                      BinaryOperator::CreateAShr(VarX, Amt);
1122       if (cast<BinaryOperator>(Shr)->isExact())
1123         New->setIsExact(true);
1124     }
1125 
1126     return InsertNewInstWith(New, *Shl);
1127   }
1128 
1129   return nullptr;
1130 }
1131 
1132 /// The specified value produces a vector with any number of elements.
1133 /// This method analyzes which elements of the operand are undef or poison and
1134 /// returns that information in UndefElts.
1135 ///
1136 /// DemandedElts contains the set of elements that are actually used by the
1137 /// caller, and by default (AllowMultipleUsers equals false) the value is
1138 /// simplified only if it has a single caller. If AllowMultipleUsers is set
1139 /// to true, DemandedElts refers to the union of sets of elements that are
1140 /// used by all callers.
1141 ///
1142 /// If the information about demanded elements can be used to simplify the
1143 /// operation, the operation is simplified, then the resultant value is
1144 /// returned.  This returns null if no change was made.
1145 Value *InstCombinerImpl::SimplifyDemandedVectorElts(Value *V,
1146                                                     APInt DemandedElts,
1147                                                     APInt &UndefElts,
1148                                                     unsigned Depth,
1149                                                     bool AllowMultipleUsers) {
1150   // Cannot analyze scalable type. The number of vector elements is not a
1151   // compile-time constant.
1152   if (isa<ScalableVectorType>(V->getType()))
1153     return nullptr;
1154 
1155   unsigned VWidth = cast<FixedVectorType>(V->getType())->getNumElements();
1156   APInt EltMask(APInt::getAllOnes(VWidth));
1157   assert((DemandedElts & ~EltMask) == 0 && "Invalid DemandedElts!");
1158 
1159   if (match(V, m_Undef())) {
1160     // If the entire vector is undef or poison, just return this info.
1161     UndefElts = EltMask;
1162     return nullptr;
1163   }
1164 
1165   if (DemandedElts.isZero()) { // If nothing is demanded, provide poison.
1166     UndefElts = EltMask;
1167     return PoisonValue::get(V->getType());
1168   }
1169 
1170   UndefElts = 0;
1171 
1172   if (auto *C = dyn_cast<Constant>(V)) {
1173     // Check if this is identity. If so, return 0 since we are not simplifying
1174     // anything.
1175     if (DemandedElts.isAllOnes())
1176       return nullptr;
1177 
1178     Type *EltTy = cast<VectorType>(V->getType())->getElementType();
1179     Constant *Poison = PoisonValue::get(EltTy);
1180     SmallVector<Constant*, 16> Elts;
1181     for (unsigned i = 0; i != VWidth; ++i) {
1182       if (!DemandedElts[i]) {   // If not demanded, set to poison.
1183         Elts.push_back(Poison);
1184         UndefElts.setBit(i);
1185         continue;
1186       }
1187 
1188       Constant *Elt = C->getAggregateElement(i);
1189       if (!Elt) return nullptr;
1190 
1191       Elts.push_back(Elt);
1192       if (isa<UndefValue>(Elt))   // Already undef or poison.
1193         UndefElts.setBit(i);
1194     }
1195 
1196     // If we changed the constant, return it.
1197     Constant *NewCV = ConstantVector::get(Elts);
1198     return NewCV != C ? NewCV : nullptr;
1199   }
1200 
1201   // Limit search depth.
1202   if (Depth == 10)
1203     return nullptr;
1204 
1205   if (!AllowMultipleUsers) {
1206     // If multiple users are using the root value, proceed with
1207     // simplification conservatively assuming that all elements
1208     // are needed.
1209     if (!V->hasOneUse()) {
1210       // Quit if we find multiple users of a non-root value though.
1211       // They'll be handled when it's their turn to be visited by
1212       // the main instcombine process.
1213       if (Depth != 0)
1214         // TODO: Just compute the UndefElts information recursively.
1215         return nullptr;
1216 
1217       // Conservatively assume that all elements are needed.
1218       DemandedElts = EltMask;
1219     }
1220   }
1221 
1222   Instruction *I = dyn_cast<Instruction>(V);
1223   if (!I) return nullptr;        // Only analyze instructions.
1224 
1225   bool MadeChange = false;
1226   auto simplifyAndSetOp = [&](Instruction *Inst, unsigned OpNum,
1227                               APInt Demanded, APInt &Undef) {
1228     auto *II = dyn_cast<IntrinsicInst>(Inst);
1229     Value *Op = II ? II->getArgOperand(OpNum) : Inst->getOperand(OpNum);
1230     if (Value *V = SimplifyDemandedVectorElts(Op, Demanded, Undef, Depth + 1)) {
1231       replaceOperand(*Inst, OpNum, V);
1232       MadeChange = true;
1233     }
1234   };
1235 
1236   APInt UndefElts2(VWidth, 0);
1237   APInt UndefElts3(VWidth, 0);
1238   switch (I->getOpcode()) {
1239   default: break;
1240 
1241   case Instruction::GetElementPtr: {
1242     // The LangRef requires that struct geps have all constant indices.  As
1243     // such, we can't convert any operand to partial undef.
1244     auto mayIndexStructType = [](GetElementPtrInst &GEP) {
1245       for (auto I = gep_type_begin(GEP), E = gep_type_end(GEP);
1246            I != E; I++)
1247         if (I.isStruct())
1248           return true;
1249       return false;
1250     };
1251     if (mayIndexStructType(cast<GetElementPtrInst>(*I)))
1252       break;
1253 
1254     // Conservatively track the demanded elements back through any vector
1255     // operands we may have.  We know there must be at least one, or we
1256     // wouldn't have a vector result to get here. Note that we intentionally
1257     // merge the undef bits here since gepping with either an poison base or
1258     // index results in poison.
1259     for (unsigned i = 0; i < I->getNumOperands(); i++) {
1260       if (i == 0 ? match(I->getOperand(i), m_Undef())
1261                  : match(I->getOperand(i), m_Poison())) {
1262         // If the entire vector is undefined, just return this info.
1263         UndefElts = EltMask;
1264         return nullptr;
1265       }
1266       if (I->getOperand(i)->getType()->isVectorTy()) {
1267         APInt UndefEltsOp(VWidth, 0);
1268         simplifyAndSetOp(I, i, DemandedElts, UndefEltsOp);
1269         // gep(x, undef) is not undef, so skip considering idx ops here
1270         // Note that we could propagate poison, but we can't distinguish between
1271         // undef & poison bits ATM
1272         if (i == 0)
1273           UndefElts |= UndefEltsOp;
1274       }
1275     }
1276 
1277     break;
1278   }
1279   case Instruction::InsertElement: {
1280     // If this is a variable index, we don't know which element it overwrites.
1281     // demand exactly the same input as we produce.
1282     ConstantInt *Idx = dyn_cast<ConstantInt>(I->getOperand(2));
1283     if (!Idx) {
1284       // Note that we can't propagate undef elt info, because we don't know
1285       // which elt is getting updated.
1286       simplifyAndSetOp(I, 0, DemandedElts, UndefElts2);
1287       break;
1288     }
1289 
1290     // The element inserted overwrites whatever was there, so the input demanded
1291     // set is simpler than the output set.
1292     unsigned IdxNo = Idx->getZExtValue();
1293     APInt PreInsertDemandedElts = DemandedElts;
1294     if (IdxNo < VWidth)
1295       PreInsertDemandedElts.clearBit(IdxNo);
1296 
1297     // If we only demand the element that is being inserted and that element
1298     // was extracted from the same index in another vector with the same type,
1299     // replace this insert with that other vector.
1300     // Note: This is attempted before the call to simplifyAndSetOp because that
1301     //       may change UndefElts to a value that does not match with Vec.
1302     Value *Vec;
1303     if (PreInsertDemandedElts == 0 &&
1304         match(I->getOperand(1),
1305               m_ExtractElt(m_Value(Vec), m_SpecificInt(IdxNo))) &&
1306         Vec->getType() == I->getType()) {
1307       return Vec;
1308     }
1309 
1310     simplifyAndSetOp(I, 0, PreInsertDemandedElts, UndefElts);
1311 
1312     // If this is inserting an element that isn't demanded, remove this
1313     // insertelement.
1314     if (IdxNo >= VWidth || !DemandedElts[IdxNo]) {
1315       Worklist.push(I);
1316       return I->getOperand(0);
1317     }
1318 
1319     // The inserted element is defined.
1320     UndefElts.clearBit(IdxNo);
1321     break;
1322   }
1323   case Instruction::ShuffleVector: {
1324     auto *Shuffle = cast<ShuffleVectorInst>(I);
1325     assert(Shuffle->getOperand(0)->getType() ==
1326            Shuffle->getOperand(1)->getType() &&
1327            "Expected shuffle operands to have same type");
1328     unsigned OpWidth = cast<FixedVectorType>(Shuffle->getOperand(0)->getType())
1329                            ->getNumElements();
1330     // Handle trivial case of a splat. Only check the first element of LHS
1331     // operand.
1332     if (all_of(Shuffle->getShuffleMask(), [](int Elt) { return Elt == 0; }) &&
1333         DemandedElts.isAllOnes()) {
1334       if (!match(I->getOperand(1), m_Undef())) {
1335         I->setOperand(1, PoisonValue::get(I->getOperand(1)->getType()));
1336         MadeChange = true;
1337       }
1338       APInt LeftDemanded(OpWidth, 1);
1339       APInt LHSUndefElts(OpWidth, 0);
1340       simplifyAndSetOp(I, 0, LeftDemanded, LHSUndefElts);
1341       if (LHSUndefElts[0])
1342         UndefElts = EltMask;
1343       else
1344         UndefElts.clearAllBits();
1345       break;
1346     }
1347 
1348     APInt LeftDemanded(OpWidth, 0), RightDemanded(OpWidth, 0);
1349     for (unsigned i = 0; i < VWidth; i++) {
1350       if (DemandedElts[i]) {
1351         unsigned MaskVal = Shuffle->getMaskValue(i);
1352         if (MaskVal != -1u) {
1353           assert(MaskVal < OpWidth * 2 &&
1354                  "shufflevector mask index out of range!");
1355           if (MaskVal < OpWidth)
1356             LeftDemanded.setBit(MaskVal);
1357           else
1358             RightDemanded.setBit(MaskVal - OpWidth);
1359         }
1360       }
1361     }
1362 
1363     APInt LHSUndefElts(OpWidth, 0);
1364     simplifyAndSetOp(I, 0, LeftDemanded, LHSUndefElts);
1365 
1366     APInt RHSUndefElts(OpWidth, 0);
1367     simplifyAndSetOp(I, 1, RightDemanded, RHSUndefElts);
1368 
1369     // If this shuffle does not change the vector length and the elements
1370     // demanded by this shuffle are an identity mask, then this shuffle is
1371     // unnecessary.
1372     //
1373     // We are assuming canonical form for the mask, so the source vector is
1374     // operand 0 and operand 1 is not used.
1375     //
1376     // Note that if an element is demanded and this shuffle mask is undefined
1377     // for that element, then the shuffle is not considered an identity
1378     // operation. The shuffle prevents poison from the operand vector from
1379     // leaking to the result by replacing poison with an undefined value.
1380     if (VWidth == OpWidth) {
1381       bool IsIdentityShuffle = true;
1382       for (unsigned i = 0; i < VWidth; i++) {
1383         unsigned MaskVal = Shuffle->getMaskValue(i);
1384         if (DemandedElts[i] && i != MaskVal) {
1385           IsIdentityShuffle = false;
1386           break;
1387         }
1388       }
1389       if (IsIdentityShuffle)
1390         return Shuffle->getOperand(0);
1391     }
1392 
1393     bool NewUndefElts = false;
1394     unsigned LHSIdx = -1u, LHSValIdx = -1u;
1395     unsigned RHSIdx = -1u, RHSValIdx = -1u;
1396     bool LHSUniform = true;
1397     bool RHSUniform = true;
1398     for (unsigned i = 0; i < VWidth; i++) {
1399       unsigned MaskVal = Shuffle->getMaskValue(i);
1400       if (MaskVal == -1u) {
1401         UndefElts.setBit(i);
1402       } else if (!DemandedElts[i]) {
1403         NewUndefElts = true;
1404         UndefElts.setBit(i);
1405       } else if (MaskVal < OpWidth) {
1406         if (LHSUndefElts[MaskVal]) {
1407           NewUndefElts = true;
1408           UndefElts.setBit(i);
1409         } else {
1410           LHSIdx = LHSIdx == -1u ? i : OpWidth;
1411           LHSValIdx = LHSValIdx == -1u ? MaskVal : OpWidth;
1412           LHSUniform = LHSUniform && (MaskVal == i);
1413         }
1414       } else {
1415         if (RHSUndefElts[MaskVal - OpWidth]) {
1416           NewUndefElts = true;
1417           UndefElts.setBit(i);
1418         } else {
1419           RHSIdx = RHSIdx == -1u ? i : OpWidth;
1420           RHSValIdx = RHSValIdx == -1u ? MaskVal - OpWidth : OpWidth;
1421           RHSUniform = RHSUniform && (MaskVal - OpWidth == i);
1422         }
1423       }
1424     }
1425 
1426     // Try to transform shuffle with constant vector and single element from
1427     // this constant vector to single insertelement instruction.
1428     // shufflevector V, C, <v1, v2, .., ci, .., vm> ->
1429     // insertelement V, C[ci], ci-n
1430     if (OpWidth ==
1431         cast<FixedVectorType>(Shuffle->getType())->getNumElements()) {
1432       Value *Op = nullptr;
1433       Constant *Value = nullptr;
1434       unsigned Idx = -1u;
1435 
1436       // Find constant vector with the single element in shuffle (LHS or RHS).
1437       if (LHSIdx < OpWidth && RHSUniform) {
1438         if (auto *CV = dyn_cast<ConstantVector>(Shuffle->getOperand(0))) {
1439           Op = Shuffle->getOperand(1);
1440           Value = CV->getOperand(LHSValIdx);
1441           Idx = LHSIdx;
1442         }
1443       }
1444       if (RHSIdx < OpWidth && LHSUniform) {
1445         if (auto *CV = dyn_cast<ConstantVector>(Shuffle->getOperand(1))) {
1446           Op = Shuffle->getOperand(0);
1447           Value = CV->getOperand(RHSValIdx);
1448           Idx = RHSIdx;
1449         }
1450       }
1451       // Found constant vector with single element - convert to insertelement.
1452       if (Op && Value) {
1453         Instruction *New = InsertElementInst::Create(
1454             Op, Value, ConstantInt::get(Type::getInt32Ty(I->getContext()), Idx),
1455             Shuffle->getName());
1456         InsertNewInstWith(New, *Shuffle);
1457         return New;
1458       }
1459     }
1460     if (NewUndefElts) {
1461       // Add additional discovered undefs.
1462       SmallVector<int, 16> Elts;
1463       for (unsigned i = 0; i < VWidth; ++i) {
1464         if (UndefElts[i])
1465           Elts.push_back(UndefMaskElem);
1466         else
1467           Elts.push_back(Shuffle->getMaskValue(i));
1468       }
1469       Shuffle->setShuffleMask(Elts);
1470       MadeChange = true;
1471     }
1472     break;
1473   }
1474   case Instruction::Select: {
1475     // If this is a vector select, try to transform the select condition based
1476     // on the current demanded elements.
1477     SelectInst *Sel = cast<SelectInst>(I);
1478     if (Sel->getCondition()->getType()->isVectorTy()) {
1479       // TODO: We are not doing anything with UndefElts based on this call.
1480       // It is overwritten below based on the other select operands. If an
1481       // element of the select condition is known undef, then we are free to
1482       // choose the output value from either arm of the select. If we know that
1483       // one of those values is undef, then the output can be undef.
1484       simplifyAndSetOp(I, 0, DemandedElts, UndefElts);
1485     }
1486 
1487     // Next, see if we can transform the arms of the select.
1488     APInt DemandedLHS(DemandedElts), DemandedRHS(DemandedElts);
1489     if (auto *CV = dyn_cast<ConstantVector>(Sel->getCondition())) {
1490       for (unsigned i = 0; i < VWidth; i++) {
1491         // isNullValue() always returns false when called on a ConstantExpr.
1492         // Skip constant expressions to avoid propagating incorrect information.
1493         Constant *CElt = CV->getAggregateElement(i);
1494         if (isa<ConstantExpr>(CElt))
1495           continue;
1496         // TODO: If a select condition element is undef, we can demand from
1497         // either side. If one side is known undef, choosing that side would
1498         // propagate undef.
1499         if (CElt->isNullValue())
1500           DemandedLHS.clearBit(i);
1501         else
1502           DemandedRHS.clearBit(i);
1503       }
1504     }
1505 
1506     simplifyAndSetOp(I, 1, DemandedLHS, UndefElts2);
1507     simplifyAndSetOp(I, 2, DemandedRHS, UndefElts3);
1508 
1509     // Output elements are undefined if the element from each arm is undefined.
1510     // TODO: This can be improved. See comment in select condition handling.
1511     UndefElts = UndefElts2 & UndefElts3;
1512     break;
1513   }
1514   case Instruction::BitCast: {
1515     // Vector->vector casts only.
1516     VectorType *VTy = dyn_cast<VectorType>(I->getOperand(0)->getType());
1517     if (!VTy) break;
1518     unsigned InVWidth = cast<FixedVectorType>(VTy)->getNumElements();
1519     APInt InputDemandedElts(InVWidth, 0);
1520     UndefElts2 = APInt(InVWidth, 0);
1521     unsigned Ratio;
1522 
1523     if (VWidth == InVWidth) {
1524       // If we are converting from <4 x i32> -> <4 x f32>, we demand the same
1525       // elements as are demanded of us.
1526       Ratio = 1;
1527       InputDemandedElts = DemandedElts;
1528     } else if ((VWidth % InVWidth) == 0) {
1529       // If the number of elements in the output is a multiple of the number of
1530       // elements in the input then an input element is live if any of the
1531       // corresponding output elements are live.
1532       Ratio = VWidth / InVWidth;
1533       for (unsigned OutIdx = 0; OutIdx != VWidth; ++OutIdx)
1534         if (DemandedElts[OutIdx])
1535           InputDemandedElts.setBit(OutIdx / Ratio);
1536     } else if ((InVWidth % VWidth) == 0) {
1537       // If the number of elements in the input is a multiple of the number of
1538       // elements in the output then an input element is live if the
1539       // corresponding output element is live.
1540       Ratio = InVWidth / VWidth;
1541       for (unsigned InIdx = 0; InIdx != InVWidth; ++InIdx)
1542         if (DemandedElts[InIdx / Ratio])
1543           InputDemandedElts.setBit(InIdx);
1544     } else {
1545       // Unsupported so far.
1546       break;
1547     }
1548 
1549     simplifyAndSetOp(I, 0, InputDemandedElts, UndefElts2);
1550 
1551     if (VWidth == InVWidth) {
1552       UndefElts = UndefElts2;
1553     } else if ((VWidth % InVWidth) == 0) {
1554       // If the number of elements in the output is a multiple of the number of
1555       // elements in the input then an output element is undef if the
1556       // corresponding input element is undef.
1557       for (unsigned OutIdx = 0; OutIdx != VWidth; ++OutIdx)
1558         if (UndefElts2[OutIdx / Ratio])
1559           UndefElts.setBit(OutIdx);
1560     } else if ((InVWidth % VWidth) == 0) {
1561       // If the number of elements in the input is a multiple of the number of
1562       // elements in the output then an output element is undef if all of the
1563       // corresponding input elements are undef.
1564       for (unsigned OutIdx = 0; OutIdx != VWidth; ++OutIdx) {
1565         APInt SubUndef = UndefElts2.lshr(OutIdx * Ratio).zextOrTrunc(Ratio);
1566         if (SubUndef.countPopulation() == Ratio)
1567           UndefElts.setBit(OutIdx);
1568       }
1569     } else {
1570       llvm_unreachable("Unimp");
1571     }
1572     break;
1573   }
1574   case Instruction::FPTrunc:
1575   case Instruction::FPExt:
1576     simplifyAndSetOp(I, 0, DemandedElts, UndefElts);
1577     break;
1578 
1579   case Instruction::Call: {
1580     IntrinsicInst *II = dyn_cast<IntrinsicInst>(I);
1581     if (!II) break;
1582     switch (II->getIntrinsicID()) {
1583     case Intrinsic::masked_gather: // fallthrough
1584     case Intrinsic::masked_load: {
1585       // Subtlety: If we load from a pointer, the pointer must be valid
1586       // regardless of whether the element is demanded.  Doing otherwise risks
1587       // segfaults which didn't exist in the original program.
1588       APInt DemandedPtrs(APInt::getAllOnes(VWidth)),
1589           DemandedPassThrough(DemandedElts);
1590       if (auto *CV = dyn_cast<ConstantVector>(II->getOperand(2)))
1591         for (unsigned i = 0; i < VWidth; i++) {
1592           Constant *CElt = CV->getAggregateElement(i);
1593           if (CElt->isNullValue())
1594             DemandedPtrs.clearBit(i);
1595           else if (CElt->isAllOnesValue())
1596             DemandedPassThrough.clearBit(i);
1597         }
1598       if (II->getIntrinsicID() == Intrinsic::masked_gather)
1599         simplifyAndSetOp(II, 0, DemandedPtrs, UndefElts2);
1600       simplifyAndSetOp(II, 3, DemandedPassThrough, UndefElts3);
1601 
1602       // Output elements are undefined if the element from both sources are.
1603       // TODO: can strengthen via mask as well.
1604       UndefElts = UndefElts2 & UndefElts3;
1605       break;
1606     }
1607     default: {
1608       // Handle target specific intrinsics
1609       Optional<Value *> V = targetSimplifyDemandedVectorEltsIntrinsic(
1610           *II, DemandedElts, UndefElts, UndefElts2, UndefElts3,
1611           simplifyAndSetOp);
1612       if (V.hasValue())
1613         return V.getValue();
1614       break;
1615     }
1616     } // switch on IntrinsicID
1617     break;
1618   } // case Call
1619   } // switch on Opcode
1620 
1621   // TODO: We bail completely on integer div/rem and shifts because they have
1622   // UB/poison potential, but that should be refined.
1623   BinaryOperator *BO;
1624   if (match(I, m_BinOp(BO)) && !BO->isIntDivRem() && !BO->isShift()) {
1625     simplifyAndSetOp(I, 0, DemandedElts, UndefElts);
1626     simplifyAndSetOp(I, 1, DemandedElts, UndefElts2);
1627 
1628     // Output elements are undefined if both are undefined. Consider things
1629     // like undef & 0. The result is known zero, not undef.
1630     UndefElts &= UndefElts2;
1631   }
1632 
1633   // If we've proven all of the lanes undef, return an undef value.
1634   // TODO: Intersect w/demanded lanes
1635   if (UndefElts.isAllOnes())
1636     return UndefValue::get(I->getType());;
1637 
1638   return MadeChange ? I : nullptr;
1639 }
1640