1=========================================== 2Control Flow Integrity Design Documentation 3=========================================== 4 5This page documents the design of the :doc:`ControlFlowIntegrity` schemes 6supported by Clang. 7 8Forward-Edge CFI for Virtual Calls 9================================== 10 11This scheme works by allocating, for each static type used to make a virtual 12call, a region of read-only storage in the object file holding a bit vector 13that maps onto to the region of storage used for those virtual tables. Each 14set bit in the bit vector corresponds to the `address point`_ for a virtual 15table compatible with the static type for which the bit vector is being built. 16 17For example, consider the following three C++ classes: 18 19.. code-block:: c++ 20 21 struct A { 22 virtual void f1(); 23 virtual void f2(); 24 virtual void f3(); 25 }; 26 27 struct B : A { 28 virtual void f1(); 29 virtual void f2(); 30 virtual void f3(); 31 }; 32 33 struct C : A { 34 virtual void f1(); 35 virtual void f2(); 36 virtual void f3(); 37 }; 38 39The scheme will cause the virtual tables for A, B and C to be laid out 40consecutively: 41 42.. csv-table:: Virtual Table Layout for A, B, C 43 :header: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 44 45 A::offset-to-top, &A::rtti, &A::f1, &A::f2, &A::f3, B::offset-to-top, &B::rtti, &B::f1, &B::f2, &B::f3, C::offset-to-top, &C::rtti, &C::f1, &C::f2, &C::f3 46 47The bit vector for static types A, B and C will look like this: 48 49.. csv-table:: Bit Vectors for A, B, C 50 :header: Class, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 51 52 A, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0 53 B, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 54 C, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0 55 56To emit a virtual call, the compiler will assemble code that checks that 57the object's virtual table pointer is in-bounds and aligned and that the 58relevant bit is set in the bit vector. 59 60For example on x86 a typical virtual call may look like this: 61 62.. code-block:: none 63 64 159a: 48 8b 03 mov (%rbx),%rax 65 159d: 48 8d 15 6c 33 00 00 lea 0x336c(%rip),%rdx 66 15a4: 48 89 c1 mov %rax,%rcx 67 15a7: 48 29 d1 sub %rdx,%rcx 68 15aa: 48 c1 c1 3d rol $0x3d,%rcx 69 15ae: 48 83 f9 51 cmp $0x51,%rcx 70 15b2: 77 3b ja 15ef <main+0xcf> 71 15b4: 48 89 ca mov %rcx,%rdx 72 15b7: 48 c1 ea 05 shr $0x5,%rdx 73 15bb: 48 8d 35 b8 07 00 00 lea 0x7b8(%rip),%rsi 74 15c2: 8b 14 96 mov (%rsi,%rdx,4),%edx 75 15c5: 0f a3 ca bt %ecx,%edx 76 15c8: 73 25 jae 15ef <main+0xcf> 77 15ca: 48 89 df mov %rbx,%rdi 78 15cd: ff 10 callq *(%rax) 79 [...] 80 15ef: 0f 0b ud2 81 82The compiler relies on co-operation from the linker in order to assemble 83the bit vectors for the whole program. It currently does this using LLVM's 84`bit sets`_ mechanism together with link-time optimization. 85 86.. _address point: https://mentorembedded.github.io/cxx-abi/abi.html#vtable-general 87.. _bit sets: http://llvm.org/docs/BitSets.html 88 89Optimizations 90------------- 91 92The scheme as described above is the fully general variant of the scheme. 93Most of the time we are able to apply one or more of the following 94optimizations to improve binary size or performance. 95 96In fact, if you try the above example with the current version of the 97compiler, you will probably find that it will not use the described virtual 98table layout or machine instructions. Some of the optimizations we are about 99to introduce cause the compiler to use a different layout or a different 100sequence of machine instructions. 101 102Stripping Leading/Trailing Zeros in Bit Vectors 103~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 104 105If a bit vector contains leading or trailing zeros, we can strip them from 106the vector. The compiler will emit code to check if the pointer is in range 107of the region covered by ones, and perform the bit vector check using a 108truncated version of the bit vector. For example, the bit vectors for our 109example class hierarchy will be emitted like this: 110 111.. csv-table:: Bit Vectors for A, B, C 112 :header: Class, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 113 114 A, , , 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, , 115 B, , , , , , , , 1, , , , , , , 116 C, , , , , , , , , , , , , 1, , 117 118Short Inline Bit Vectors 119~~~~~~~~~~~~~~~~~~~~~~~~ 120 121If the vector is sufficiently short, we can represent it as an inline constant 122on x86. This saves us a few instructions when reading the correct element 123of the bit vector. 124 125If the bit vector fits in 32 bits, the code looks like this: 126 127.. code-block:: none 128 129 dc2: 48 8b 03 mov (%rbx),%rax 130 dc5: 48 8d 15 14 1e 00 00 lea 0x1e14(%rip),%rdx 131 dcc: 48 89 c1 mov %rax,%rcx 132 dcf: 48 29 d1 sub %rdx,%rcx 133 dd2: 48 c1 c1 3d rol $0x3d,%rcx 134 dd6: 48 83 f9 03 cmp $0x3,%rcx 135 dda: 77 2f ja e0b <main+0x9b> 136 ddc: ba 09 00 00 00 mov $0x9,%edx 137 de1: 0f a3 ca bt %ecx,%edx 138 de4: 73 25 jae e0b <main+0x9b> 139 de6: 48 89 df mov %rbx,%rdi 140 de9: ff 10 callq *(%rax) 141 [...] 142 e0b: 0f 0b ud2 143 144Or if the bit vector fits in 64 bits: 145 146.. code-block:: none 147 148 11a6: 48 8b 03 mov (%rbx),%rax 149 11a9: 48 8d 15 d0 28 00 00 lea 0x28d0(%rip),%rdx 150 11b0: 48 89 c1 mov %rax,%rcx 151 11b3: 48 29 d1 sub %rdx,%rcx 152 11b6: 48 c1 c1 3d rol $0x3d,%rcx 153 11ba: 48 83 f9 2a cmp $0x2a,%rcx 154 11be: 77 35 ja 11f5 <main+0xb5> 155 11c0: 48 ba 09 00 00 00 00 movabs $0x40000000009,%rdx 156 11c7: 04 00 00 157 11ca: 48 0f a3 ca bt %rcx,%rdx 158 11ce: 73 25 jae 11f5 <main+0xb5> 159 11d0: 48 89 df mov %rbx,%rdi 160 11d3: ff 10 callq *(%rax) 161 [...] 162 11f5: 0f 0b ud2 163 164If the bit vector consists of a single bit, there is only one possible 165virtual table, and the check can consist of a single equality comparison: 166 167.. code-block:: none 168 169 9a2: 48 8b 03 mov (%rbx),%rax 170 9a5: 48 8d 0d a4 13 00 00 lea 0x13a4(%rip),%rcx 171 9ac: 48 39 c8 cmp %rcx,%rax 172 9af: 75 25 jne 9d6 <main+0x86> 173 9b1: 48 89 df mov %rbx,%rdi 174 9b4: ff 10 callq *(%rax) 175 [...] 176 9d6: 0f 0b ud2 177 178Virtual Table Layout 179~~~~~~~~~~~~~~~~~~~~ 180 181The compiler lays out classes of disjoint hierarchies in separate regions 182of the object file. At worst, bit vectors in disjoint hierarchies only 183need to cover their disjoint hierarchy. But the closer that classes in 184sub-hierarchies are laid out to each other, the smaller the bit vectors for 185those sub-hierarchies need to be (see "Stripping Leading/Trailing Zeros in Bit 186Vectors" above). The `GlobalLayoutBuilder`_ class is responsible for laying 187out the globals efficiently to minimize the sizes of the underlying bitsets. 188 189.. _GlobalLayoutBuilder: http://llvm.org/viewvc/llvm-project/llvm/trunk/include/llvm/Transforms/IPO/LowerBitSets.h?view=markup 190 191Alignment 192~~~~~~~~~ 193 194If all gaps between address points in a particular bit vector are multiples 195of powers of 2, the compiler can compress the bit vector by strengthening 196the alignment requirements of the virtual table pointer. For example, given 197this class hierarchy: 198 199.. code-block:: c++ 200 201 struct A { 202 virtual void f1(); 203 virtual void f2(); 204 }; 205 206 struct B : A { 207 virtual void f1(); 208 virtual void f2(); 209 virtual void f3(); 210 virtual void f4(); 211 virtual void f5(); 212 virtual void f6(); 213 }; 214 215 struct C : A { 216 virtual void f1(); 217 virtual void f2(); 218 }; 219 220The virtual tables will be laid out like this: 221 222.. csv-table:: Virtual Table Layout for A, B, C 223 :header: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 224 225 A::offset-to-top, &A::rtti, &A::f1, &A::f2, B::offset-to-top, &B::rtti, &B::f1, &B::f2, &B::f3, &B::f4, &B::f5, &B::f6, C::offset-to-top, &C::rtti, &C::f1, &C::f2 226 227Notice that each address point for A is separated by 4 words. This lets us 228emit a compressed bit vector for A that looks like this: 229 230.. csv-table:: 231 :header: 2, 6, 10, 14 232 233 1, 1, 0, 1 234 235At call sites, the compiler will strengthen the alignment requirements by 236using a different rotate count. For example, on a 64-bit machine where the 237address points are 4-word aligned (as in A from our example), the ``rol`` 238instruction may look like this: 239 240.. code-block:: none 241 242 dd2: 48 c1 c1 3b rol $0x3b,%rcx 243 244Padding to Powers of 2 245~~~~~~~~~~~~~~~~~~~~~~ 246 247Of course, this alignment scheme works best if the address points are 248in fact aligned correctly. To make this more likely to happen, we insert 249padding between virtual tables that in many cases aligns address points to 250a power of 2. Specifically, our padding aligns virtual tables to the next 251highest power of 2 bytes; because address points for specific base classes 252normally appear at fixed offsets within the virtual table, this normally 253has the effect of aligning the address points as well. 254 255This scheme introduces tradeoffs between decreased space overhead for 256instructions and bit vectors and increased overhead in the form of padding. We 257therefore limit the amount of padding so that we align to no more than 128 258bytes. This number was found experimentally to provide a good tradeoff. 259 260Eliminating Bit Vector Checks for All-Ones Bit Vectors 261~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 262 263If the bit vector is all ones, the bit vector check is redundant; we simply 264need to check that the address is in range and well aligned. This is more 265likely to occur if the virtual tables are padded. 266