Searched refs:hasSubstr (Results 1 – 1 of 1) sorted by relevance
1590 const bool hasSubstr = !xbox.substr().empty(); in matchAndRewrite() local1599 } else if (hasSubstr) { in matchAndRewrite()1658 if (hasShift && !(hasSlice || hasSubcomp || hasSubstr) && in matchAndRewrite()1695 if (hasSlice || hasSubcomp || hasSubstr) { in matchAndRewrite()1701 if (hasSubstr) in matchAndRewrite()