Searched refs:SubRegisterIndex (Results 1 – 3 of 3) sorted by relevance
170 SubRegisterIndex, enumerator
385 return lexName(C, Token, MIToken::SubRegisterIndex, Rule.size(), in maybeLexSubRegisterIndex()
2162 assert(Token.is(MIToken::SubRegisterIndex)); in parseSubRegisterIndexOperand()2800 case MIToken::SubRegisterIndex: in parseMachineOperand()