Searched refs:aiColumn (Results 1 – 2 of 2) sorted by relevance
93375 if( pIdx->aiColumn[j]==iCol || pIdx->aiColumn[j]==XN_EXPR ){111984 j = pPk->aiColumn[iCol];112117 testcase( hasColumn(pPk->aiColumn, j, pPk->aiColumn[i]) );112120 pPk->aiColumn[j++] = pPk->aiColumn[i];112150 testcase( hasColumn(pIdx->aiColumn, pIdx->nKeyCol, pPk->aiColumn[i]) );112162 testcase( hasColumn(pIdx->aiColumn, pIdx->nKeyCol, pPk->aiColumn[i]) );112163 pIdx->aiColumn[j] = pPk->aiColumn[i];113909 if( pIdx->aiColumn[k]!=pIndex->aiColumn[k] ) break;116609 && pPrior->aiColumn[j]==pIdx->aiColumn[j]122621 if( pSrc->aiColumn[i]!=pDest->aiColumn[i] ){[all …]
80377 if( pIdx->aiColumn[0]==i ){81835 pIndex->aiColumn[i] = j;81898 if( pIdx->aiColumn[k]!=pIndex->aiColumn[k] ) break;84030 int idx = pIdx->aiColumn[j];86174 iCol = pIdx->aiColumn[i];88441 if( pSrc->aiColumn[i]!=pDest->aiColumn[i] ){102429 pIdx->aiColumn[n] = i;102436 pIdx->aiColumn[n] = i;103255 sPk.aiColumn = &aiColumnPk;103926 int k = pIdx->aiColumn[j];[all …]