Searched refs:enc2 (Results 1 – 3 of 3) sorted by relevance
10 const enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);23 keyset.charAt(enc2) +
1 …enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);\n let enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);\n let…
13 const enc2 = ((chr1 & 3) << 4) | (chr2 >> 4); constant26 keyset.charAt(enc2) +